| 文中提及函数并非Oracle及SQL Server 的全部功能,尤其分析挖掘函数,并未完全涵盖,请以实际解决问题优先,勿妄谈二者优劣。 
 1.绝对值
 S:select abs(-1) value
 O:select abs(-1) value from dual
 
 2.取整(大)
 S:select ceiling(-1.001) value
 O:select ceil(-1.001) value from dual
 
 3.取整(小)
 S:select floor(-1.001) value
 O:select floor(-1.001) value from dual
 
 4.取整(截取)
 S:select cast(-1.002 as int) value
 O:select trunc(-1.002) value from dual
 
 5.四舍五入
 S:select round(1.23456,4) value 1.23460
 O:select round(1.23456,4) value from dual 1.2346
 
 6.e为底的幂
 S:select Exp(1) value 2.7182818284590451
 O:select Exp(1) value from dual 2.71828182
 
 7.取e为底的对数
 S:select log(2.7182818284590451) value 1
 O:select ln(2.7182818284590451) value from dual; 1
 
 8.取10为底对数
 S:select log10(10) value 1
 O:select log(10,10) value from dual; 1
 
 9.取平方
 S:select SQUARE(4) value 16
 O:select power(4,2) value from dual 16
 
 10.取平方根
 S:select SQRT(4) value 2
 O:select SQRT(4) value from dual 2
 
 11.求任意数为底的幂
 S:select power(3,4) value 81
 O:select power(3,4) value from dual 81
 
 12.取随机数
 S:select rand() value
 O:select sys.dbms_random.value(0,1) value from dual;
 
 13.取符号
 S:select sign(-8) value -1
 O:select sign(-8) value from dual -1
 
 ----------数学函数
 
 14.圆周率
 S:SELECT PI() value 3.1415926535897931
 O:不知道
 
 15.sin,cos,tan 参数都以弧度为单位
 例如:select sin(PI()/2) value 得到1(SQLServer)
 
 16.Asin,Acos,Atan,Atan2 返回弧度
 
 17.弧度角度互换(SQLServer,Oracle不知道)
 DEGREES:弧度-〉角度
 RADIANS:角度-〉弧度
 
 ---------数值间比较
 
 18. 求集合最大值
 S:select max(value) value from
 (select 1 value
 union
 select -2 value
 union
 select 4 value
 union
 select 3 value)a
 
 O:select greatest(1,-2,4,3) value from dual
 
 19. 求集合最小值
 S:select min(value) value from
 (select 1 value
 union
 select -2 value
 union
 select 4 value
 union
 select 3 value)a
 
 O:select least(1,3) value from dual
 
 20.如何处理null值(F2中的null以10代替)
 S:select F1,IsNull(F2,10) value from Tbl
 O:select F1,nvl(F2,10) value from Tbl
 
 --------数值间比较
 
 21.求字符序号
 S:select ascii('a') value
 O:select ascii('a') value from dual
 
 22.从序号求字符
 S:select char(97) value
 O:select chr(97) value from dual
 
 23.连接
 S:select '11'+'22'+'33' value
 O:select CONCAT('11','22')||33 value from dual
 
 23.子串位置 --返回3
 S:select CHARINDEX('s','sdsq',2) value
 O:select INSTR('sdsq','s',2) value from dual
 
 23.模糊子串的位置 --返回2,参数去掉中间%则返回7
 S:select patindex('%d%q%','sdsfasdqe') value
 O:oracle没发现,但是instr可以通过第四个参数控制出现次数
 select INSTR('sdsfasdqe','sd',1,2) value from dual 返回6
 
 
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